Need Help: Wiring LEDs with 2 source voltages
#LED
#brightness control
#bike lights
#running lights
#brake lights
#voltage control
#series circuit
#current limiting
#automotive circuits
#DIY electronics
Description: A series of LEDs is intended to display at two brightness levels, and there is uncertainty regarding the proper wiring. This setup is for additional running lights and brake lights on a bicycle. When using the series LED calculator, it is suggested to set the forward voltage to 1.1V and the forward current to 75mA for Source Voltage 1. Similarly, Source Voltage 2 should also be set to 1.1V and 75mA. This configuration would yield a total of 2.2V and 150mA.
To achieve the desired functionality of displaying two brightness levels for the LED lights, a dual-resistor approach can be employed. The circuit should include a pair of series-connected LEDs, each rated for a forward voltage of 1.1V and a forward current of 75mA. When connected in series, the total forward voltage drop across the two LEDs will be 2.2V, while the current flow through the circuit will remain at 75mA.
To implement the two brightness levels, a switching mechanism can be introduced. This can be accomplished using a transistor or a MOSFET, which will allow for the control of current flowing through the LEDs. In the first brightness level, the full current of 75mA can be allowed to flow, while in the second brightness level, a resistor can be placed in series with the LEDs to reduce the current, thereby dimming the lights.
For the resistor calculation, the desired current for the dimmed state should be established. For example, if the target current for the dimmed state is 37.5mA, the series resistor can be calculated using Ohm's Law. The voltage across the resistor can be determined by taking the difference between the source voltage and the total forward voltage of the LEDs (2.2V).
If a 5V supply is used, the voltage across the resistor would be 5V - 2.2V = 2.8V. The required resistance to achieve 37.5mA can be calculated as follows: R = V/I = 2.8V / 0.0375A = 74.67 ohms. A standard resistor value of 75 ohms can be selected.
In summary, the circuit will consist of two series LEDs, a switching mechanism to alternate between brightness levels, and a series resistor for the dimmed state. Proper attention should be given to the power ratings of the components to ensure safe operation. The power rating for the resistor can be calculated using P = I^2 * R, which should exceed the calculated power to prevent overheating. This design will effectively provide the desired functionality for additional running lights and brake lights on the bicycle.A series of LEDs I would like to have display at 2 brightness levels and am confused how to properly wire this. This is for additional running lights/brake lights on my bike. When using the series LED calculator I believe for the Source voltage 1 I should set the forward voltage to 1.
1V and 75ma (half of typical voltage and half of forwardcurrent) and then set the Source Voltage 2 to 1. 1V and 75ma (the other half of voltage and forward current). That in my eyes would result 2. 2V and 150ma.
To achieve the desired functionality of displaying two brightness levels for the LED lights, a dual-resistor approach can be employed. The circuit should include a pair of series-connected LEDs, each rated for a forward voltage of 1.1V and a forward current of 75mA. When connected in series, the total forward voltage drop across the two LEDs will be 2.2V, while the current flow through the circuit will remain at 75mA.
To implement the two brightness levels, a switching mechanism can be introduced. This can be accomplished using a transistor or a MOSFET, which will allow for the control of current flowing through the LEDs. In the first brightness level, the full current of 75mA can be allowed to flow, while in the second brightness level, a resistor can be placed in series with the LEDs to reduce the current, thereby dimming the lights.
For the resistor calculation, the desired current for the dimmed state should be established. For example, if the target current for the dimmed state is 37.5mA, the series resistor can be calculated using Ohm's Law. The voltage across the resistor can be determined by taking the difference between the source voltage and the total forward voltage of the LEDs (2.2V).
If a 5V supply is used, the voltage across the resistor would be 5V - 2.2V = 2.8V. The required resistance to achieve 37.5mA can be calculated as follows: R = V/I = 2.8V / 0.0375A = 74.67 ohms. A standard resistor value of 75 ohms can be selected.
In summary, the circuit will consist of two series LEDs, a switching mechanism to alternate between brightness levels, and a series resistor for the dimmed state. Proper attention should be given to the power ratings of the components to ensure safe operation. The power rating for the resistor can be calculated using P = I^2 * R, which should exceed the calculated power to prevent overheating. This design will effectively provide the desired functionality for additional running lights and brake lights on the bicycle.A series of LEDs I would like to have display at 2 brightness levels and am confused how to properly wire this. This is for additional running lights/brake lights on my bike. When using the series LED calculator I believe for the Source voltage 1 I should set the forward voltage to 1.
1V and 75ma (half of typical voltage and half of forwardcurrent) and then set the Source Voltage 2 to 1. 1V and 75ma (the other half of voltage and forward current). That in my eyes would result 2. 2V and 150ma.
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